δ18O
The 18O concentration of VSMOW is
2005.2 ppm which is defined as δ18O = 0.0
‰ on the VSMOW
scale.
Conversion from δ18O to ppm 18O
is linear:
conc 18O [ppm] = (1000 + δ18O
) x 2.0052
δ18O = 0 ‰ (VSMOW)
is equivalent to an 18O concentration of
2005.2 ppm
δ18O = -55.5 ‰ (SLAP)
is equivalent to an 18O concentration of
1893.91 ppm
Our lab water has δ18O =
-7.75 ‰ ( equivalent to an 18O
concentration of 1990 ppm)
δ18O = -1000 ‰ is
equivalent to an 18O concentration of 0 ppm
thus 18O-free water.
Picarro
claims their L2130-i
CRDS machines have standard deviations of 0.03
‰ for δ18O.
this is equivalent to a standard deviation of 0.06 ppm at
a concentrations around 1900 to 2000 ppm !!
Simple conversion of 18O concentration
to δ notation on the VSMOW scale
δ18O [‰]
= conc 18O / 2.0052 -
1000
(conc 18O in ppm)
δ D = δ 2H
The deuterium
(D, 2H) concentration of VSMOW is 155.76
ppm which is defined as δ 2H = 0.0
‰ on the VSMOW scale
The conversion from δ 2H to
2H concentration in ppm is linear:
conc 2H [ppm] = (1000 + δ
2H) x 0.15576
δ 2H = 0 ‰ (VSMOW) is
equivalent to a 2H concentration of 155.76 ppm
δ 2H = -427.5 ‰ (SLAP) is
equivalent to a 2H concentration of 89.173 ppm
Our lab water has δ 2H
= -52.3 ‰ ( equivalent to a 2H
concentration of 147.6 ppm)
δ 2H = -1000 ‰ is equivalent to a
2H concentration of 0 ppm thus deuterium-free
water.
Picarro claims their L2130-i CRDS machines have standard
deviations of 0.3‰ for δ 2H.
this is equivalent to a standard deviation of 0.047 ppm at
concentrations around 90 to 160 ppm !!
Simple conversion from 2H concentration
in ppm to δ 2H in ‰ on the VSMOW
scale
δ 2H [‰]
= ppm D / 0.15576 - 1000
100% heavy
water (D2O) is equivalent to a 2H
concentration of 1000000 ppm.
This corresponds to δ 2H
[‰] =1000000 / 0.15576 - 1000 = + 6419135
‰ !! (almost 6.5 Mio ‰)
Since the conversions are linear, you can calculate
linear mixtures of two solutions in either
concentrations or in δ notation.
e.g. a 1+1 mix of SLAP (δ 2H =
-427.5 ‰) and VSMOW (δ 2H
= 0 ‰) :
δ 2H = (1x(-427.5)+1x0) / (1+1) =
-213.75 ‰ or (1x89.173 ppm + 1x 155.76 ppm) / (1+1)
= 122.4665 ppm
δ 2H = 122.4665 / 0.15576 - 1000 = 786.25 -
1000 = - 213.75 ‰
1 part heavy water ( δ2H = 6419135
‰ ) + 99 parts pure water ( δ2H =
-52.3 ‰ - this counts for our lab water)
= (1x6419135+99x(-52.3)) / (1+99) = + 64139.573 ‰
so a 1% D2O solution has a δ 2H
= + 64140 ‰ or 10146 ppm 2H
If you dilute more to get a 0.01% D2O
solution (1 part heavy water + 9999 parts pure
water)
= (1x6419135 + 9999x(-52.3)) / (1+9999) = + 589.619 ‰
so a 0.01% D2O solution has a δ 2H
= + 589.62 ‰ or 247.59 ppm 2H
If you have enough house standards to choose from, you
can mix your own VSMOW
and SLAP
All δ values on this page are related to the VSMOW
scale
original time stamp 06.April 2016, edit 7, 15 Feb
2018, 06 Sep 18, 29Jan19, 22.Jul20, 05.Dec24
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